This question was previously asked in

SSC JE EE Previous Paper 11 (Held on: 24 March 2021 Morning)

Option 3 : 0.99

**Concept:**

**Precision: A measurement of consistency or repeatability of measurement** i.e., successive reading does not differ.

The **average of the measured value** is given by,

\(\overline {{X_n}} = \sum \frac{{{X_n}}}{n}\)

Where X_{n }is the recorded readings, n is no. of recorded readings.

**Precision for particular reading** is given by,

**Precision** \( = 1 - \left| {\frac{{Respective\;Reading - \overline {{X_n}} }}{{\overline {{X_n}} }}} \right|\)

__Calculation:__

The average measurement value

\(\overline {{X_n}} = \frac{{98 + 101 + 99 + 100 + 102}}{5}\)

\(= \frac{{500}}{5} = 100\)

Given third measurement reading = 99

The 3rd reading precision is given as

\(= 1 - \left| {\frac{{99 - 100}}{{100}}} \right|\)

\( = 1 - \frac{1}{{100}} = 0.99\)